18x^2-53x-11=0

Solution for 18x^2-53x-11=0 equation:

18x^2-53x-11=0

a = 18; b = -53; c = -11;
Δ = b2-4ac
Δ = -532-4·18·(-11)
Δ = 3601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-\sqrt{3601}}{2*18}=\frac{53-\sqrt{3601}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+\sqrt{3601}}{2*18}=\frac{53+\sqrt{3601}}{36}
$